"Please do this task correctly "

"do not copy from other chegg answers "

Thank you

Task 3: Environment Variables and execve() In this task, we study how environment variables are affected when a new program is executed via execve ( ). The function execve ( ) calls a system call to load a new command and execute it; this function never returns. No new process is created; instead, the calling process's text, data, bss, and stack are overwritten by that of the program loaded. Essentially, execve () runs the new program inside the calling process. We are interested in what happens to the environment variables; are they automatically inherited by the new program? - Step 1. Please compile and run the myenv. c program, and describe your observation. This program simply executes a program called /usr/bin/env, which prints out the environment variables of the current process. \#include extern char **environ; int main() char argv [2]; argv 0]= "/usr/bin/env"; argv[1] = NULL; execve("/usr/bin/env", argv, NULL); // Line 1 return 0; \} - Step 2. Change the invocation of execve( ) in Line 1 to the following; describe your observation: execve("/usr/bin/env", argv, environ); - Step 3. Please draw your conclusion regarding how the new program gets its environment variables