Please don't copy from other answers because they're wrong.

Please help me with this MIPS problem:

Shifting a positive integer left by i bits gives the same result as multiplying the same integer by 2i. N2i=N>i Given an integer N stored at memory address 5000 , write a program that stores the result of N8 at memory address 5004 and the result of N/16 at memory address 5008. Use the ' + ' button under the Memory display to initialize the memory at address 5000. Ex: If the content at memory address 5000 is initialized in the simulator as 64, the data memory will contain: Note: Shift-right performs an integer division; therefore, digits after the decimal point are ignored