Question: Please explain 1. Counting atoms begin{tabular}{|l|l|} hline multicolumn{1}{|c|}{ Compound } & multicolumn{1}{c|}{ Total No. of Atoms } hline Mg3(PO3)2 & 3Mg+2P+60=11 hline Ca(PO4)2

Please explain Please explain 1. Counting atoms \begin{tabular}{|l|l|} \hline \multicolumn{1}{|c|}{ Compound } & \multicolumn{1}{c|}{

1. Counting atoms \begin{tabular}{|l|l|} \hline \multicolumn{1}{|c|}{ Compound } & \multicolumn{1}{c|}{ Total No. of Atoms } \\ \hline Mg3(PO3)2 & 3Mg+2P+60=11 \\ \hline Ca(PO4)2 & \\ \hline BeAl2(SiO3)6. gemstoneryl. The mineral which is the source of the \\ \hline(NH4)2SO3 & \\ \hline \end{tabular}

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