Question: please explain A trough whose cross section is a semicircle of radius r = 10 i is filled with water to a depth of h

please explain

A trough whose cross section is a semicircle of radius r = 10 i is filled with water to a depth of h = 5 m. What is the force due to water pressure on one end of the trough? (Hint. The mass density of water is 1000 kg/m, g = 9.8 m/s-5 Use decimal notation. Give your answer to the nearest whole number. Express your answer in kilonewtons (recall that 1 KN = 1000 N.))

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