Question: please explain answer 41. A study was conducted to examine the difference in the number of cigarettes smoked in a day between two quit-smoking medications.
please explain answer

41. A study was conducted to examine the difference in the number of cigarettes smoked in a day between two quit-smoking medications. The average number of cigarettes smoked was 114.1375 with a standard deviation oi 4.32 among patients on the experimental quit-smoking medication. The average was 12 with a standard deviation at 3.95 among patients on a meditation currently on the market. Assume the number of cigarettes smoked follows a nomutl distribution. Group Statistics Medication N Mean SliDeviat'Lon _ New 16 14.1375 4.32387 \"Mismm Current 20 12. 0000 394702 Independent Samples Ilast Levene's 151 for Equality of variances ttest for Equality of Means F Sig. I df Sig.(2-tai1ed) . Equal variances assumed .448 .503 1.534 34 .122 meaismnk'd Equal variances not 1.563 30.344 .127 What is the correct conclusion about the null hypothesis? t= 1.534, 01 = 34, p = 0.122 > 0.05; on to reject 1-1 . t= 1.553, 01 = 30.34, p = 0.127 > 0.05; tail 1 reject H . t= 1.504, 01 = 34, p = 0.122 > 0.05; reject H n t = 1.568, 01 = 30.34, p = 0.127 > 0,05; reject H n
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
