Question: Please explain how each is expanded and if I even have the right answers: The function F = CD E + CDE + A D

Please explain how each is expanded and if I even have the right answers:
The function F = CDE + CDE + ADE + ABDE+ BCD is to be implemented in an FPGA which uses 3-variable lookup tables.
(a) Expand F about the variables A and B.
F = AB(CDE)+AB(CDE+CD)+AB(DE+C+CD)+AB(DE+CDE)
(b) Expand F about the variables B and C.
F = BC(D)+BC(DE+A)+BC(DE+AD)+BC(DE+DE)
(c) Expand F about the variables A and C.
F = AC(BDE+B)+AC(BDE)+AC(BDE+DE)+AC(BDE+DE+BD)
(d) Use your preceding answers to implement F using only three 3-variable lookup tables and a 4-to-1 MUX. Give the truth tables for the lookup tables. Attach files of your circuit implementation and your truth table.

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