Question: Please explain how they got the grey highlighted answer. Thanks! 17) I had started using that liquid sugar, which was just sugar dissolved in water.

Please explain how they got the grey highlighted answer. Thanks! Please explain how they got the grey highlighted answer. Thanks! 17) I

17) I had started using that liquid sugar, which was just sugar dissolved in water. It is really thick because of all the sugar dissolved in it. However, I was drinking water in the lab and accidentally, I think, put in some ethylene glycol that I was using for an experiment in my tea. Anyway, idiocy aside, I wanted to test the solutions boiling point and freezing point to see if I had put any in, as it would taste sweet no matter what. Ethylene glycol (EG), CH2(OH)CH2(OH), is a common automobile antifreeze. It is water soluble and fairly nonvolatile (b.p. 197C ). Calculate the boiling point and freezing point of a solution containing 455.5g of ethylene glycol in 3707g water. Assume this solution is only water and EG. New BP =101.3C New FP=3.68C

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