Please explain in detail why the critical value for the Z distribution equal to 2.05. I don't need to know anything else - you only need to explain how they are using the normal distribution table to get the critical value for the z distribution to equal 2.05

A random sample of size n, =21, taken from a normal population with a standard deviation of =6, has a mean x, = 85. A second random sample of size n, =31, taken from a different normal population with a standard deviation o, =4, has a mean x, = 38. Find a 96% confidence interval for , - 12- Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table.For the purposes of this solution, use the formula. First find the value of a for a 96% confidence interval. a = .04 (Type an integer or a decimal. Do not round.) Now find o / 2. a /2= .02 (Type an integer or a decimal. Do not round.) Find the critical value of the Z-distribution, Z, /2. While either technology or a standard normal distribution table could be used, for the purposes of this solution, use a table. Za/2 =Zo.02 = 2.05 (Round to two decimal places as needed.)