Please explain me with the equations.

Two technicians, working separately, monitor a group of five computers that run an automated manufacturing facility. It takes an average of 20 minutes (exponentially distributed) to adjust a computer that develops a problem. Computers run for an average of 80 minutes (Poisson distributed) without requiring adjustments. Determine the following using Table D.8 a) For the 2 technicians, the number of computers waiting for service = 0.120 computers (round your response to three decimal places). b) For the 2 technicians, the average number of computers being served = 0.976 computers (round your response to three decimal places). c) For the 2 technicians, the average number of computers not working = 1.096 computers (round your response to three decimal places). Finite Queuing Table for a Population of N=5 M D F 150 2 1 200 2 1 2 . 115 553 .194 .689 284 .794 382 869 990 885 976 801 955 712 .926 628 250 1 300 2 1 Print Done Question is complete. Tap on the red indicators to see incorrect answers