Please explain the following code in DETAILS. Include an explanation of what every variable does and what role it has in the method. The method returns the size of the colony and takes as input a grid, the coordinates of a starting location, and a label. Please specify which is the grid, what are represented as the coordinates and a label. etc... Please explain step by step.

 public static Map experiment(int n, int m, int x, int y, char[][] matrix, int[][] mark, char colony) { mark[x][y] = 1; matrix[x][y] = colony; if(x != 0) if(mark[x-1][y] == 0 && matrix[x-1][y] == '1') experiment(n, m, x-1, y, matrix, mark, colony); if(y != 0) if(mark[x][y-1] == 0 && matrix[x][y-1] == '1') experiment(n, m, x, y-1, matrix, mark, colony); if(x != n-1) if(mark[x+1][y] == 0 && matrix[x+1][y] == '1') experiment(n, m, x+1, y, matrix, mark, colony); if(y != m-1) if(mark[x][y+1] == 0 && matrix[x][y+1] == '1') experiment(n, m, x, y+1, matrix, mark, colony); if(x != 0 && y != 0) if(mark[x-1][y-1] == 0 && matrix[x-1][y-1] == '1') experiment(n, m, x-1, y-1, matrix, mark, colony); if(x != 0 && y != m-1) if(mark[x-1][y+1] == 0 && matrix[x-1][y+1] == '1') experiment(n, m, x-1, y+1, matrix, mark, colony); if(x != n-1 && y != m-1) if(mark[x+1][y+1] == 0 && matrix[x+1][y+1] == '1') experiment(n, m, x+1, y+1, matrix, mark, colony); if(y != 0 && x != n-1) if(mark[x+1][y-1] == 0 && matrix[x+1][y-1] == '1') experiment(n, m, x+1, y-1, matrix, mark, colony); HashMap map = new HashMap(); for(int j = 0; j  
 
 
output:
 
  The main grid is: 00100100010000001000 00010111001100000010 01100010000000101100 01000000000000000000 00111000010000010010 00000101001100100000 The solution of the first version A: 9 B: 5 C: 3 D: 1 E: 3 F: 1 G: 3 H: 2 I: 1 J: 1