please fill it out on the image if possible make answer clear

Part 4 of 4 - Analyze (b) To find the normal force at the top of the loop, we construct a force diagram as shown, where we assume that n is downward, in the direction of my. n rig Newton's second law gives EF= mac = my where a is the centripetal acceleration. At the top of the loop, CF = ma =n+ mg. These forces are equal, so we have n + mg = R R mg Finally, solving for the normal force, we have the following. mg - mg mg x 10-3kg)(9.80 m/=]) N The direction of this force is --Select--- V -Select- Submit Skip (you cannot con upward downwardThis question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part. Tutorial Exercise A bead with a hole through it slides on a wire track. The wire is threaded through the hole in the bead, and the bead slides without friction around a loop-the-loop (see figure below). The bead is released from rest at a height h = 3.45R. A (=) What is its speed at point (@? (b) How large is the normal force on the bead at point @ if its mass is 4.55 g