Please give matlab code to solve, The velocity $v$ and the falling distance $d$ of a skydiver that experiences air resistance can be approximated by:

$v(t)=\sqrt[\phantom{2}]{\frac{mg}{k}}tanh(t\sqrt[\phantom{2}]{\frac{kg}{m}})$

$d(t)=\frac{m}{k}ln(cosh(t\sqrt[\phantom{2}]{\frac{kg}{m}}))$

where $k=0\mathrm{.}515k\frac{g}{s}$ is a constant, $m$ is the diver's mass in $kg,g=9\mathrm{.}81\frac{m}{s^2}$ is the acceleration due to gravity, and $t$ is the time in seconds since the diver started falling. These functions $v(t)$ and $d(t)$ give the velocity and falling distance of the skydiver at $t$ seconds after he$/$she jumps.

An weighs $69\mathrm{.}37$ kg $.$ Find her velocity and falling distance $23$ seconds after she jumps out of the plane.