Question: Please go step by step. Showing formulas and why each number corresponds with each part of the formula. A 12.1mL vinegar sample was titrated to

Please go step by step. Showing formulas and why each number corresponds with each part of the formula.
A 12.1mL vinegar sample was titrated to the stoichiometric equivalence point with 10.5mL1.5MNaOH. Assuming the density of vinegar is 1.00g/1mL and the molar mass of is 60.05g/mol, calculate mass percent of acetic acid in the sample. Answers: A. 78.0% B. 1.30% C. 7.8% D. 78.0%
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