please graph and plot the points

L.P. Model: 100- Minimize Subject to: 90- Z= 8X + 3Y 1X + 2Y 2 60 3X + 1Y 275 XY20 (C1) (C2) 80- 3 70-4 C2 On the graph on right, constraints C, and Cy have been plotted. 60- Using the point drawing tool, plot all the corner points for the feasible area. A 50- 40- 30- 20- 10- 01 0 10 20 30 40 60 70 80 90 100 50 L.P. Model: 100- Minimize Subject to: 90- Z= 4x + 5Y 1X + 2Y 2 80 3X + 14 275 XY20 (C1) (C2) 80- 70-4\ C2 60- On the graph on right, constraints C, and C2 have been plotted. > 50- Using the point drawing tool, plot all the corner points for the feasible area. 40- 30- 20- 10- C1 0+ 0 10 20 30 40 tox 60 70 80 90 100 Consider the following LP problem developed at Zafar Malik's Carbondale, Illinois, optical scanning firm: Maximize Subject to: Z= 1X1 + 1X2 2X1 + 1X2 572 1X1 + 2X2 572 X4,X220 (C1) (C2) The optimum solution is: X1 = 24 (round your response to two decimal places). X2 = = 24 (round your response to two decimal places). Optimal solution value Z = 48 (round your response to two decimal places). If a technical breakthrough occurred that raised the profit per unit of X1 to $3, due to this change, the optimal solution changes stays the same Consider the following LP problem developed at Zafar Malik's Carbondale, Illinois, optical scanning firm: Maximize Subject to: Z= 1X1 + 1X2 2X1 + 1X2 5 100 1X1 + 2X2 = 100 X4,X220 (C1) (C2) The optimum solution is: X1 = = 33.33 (round your response to two decimal places). X2 = = 33.33 (round your response to two decimal places). Optimal solution value Z = 66.67 (round your response to two decimal places). If a technical breakthrough occurred that raised the profit per unit of X1 to $3, due to this change, the optimal solution changes stays the same