Question: Please help! 1. A solid is formed between x) and the x-axis so each slice (perpendicular to the x-axis) is a right triangle whose base




Please help!
1.






A solid is formed between x) and the x-axis so each slice (perpendicular to the x-axis) is a right triangle whose base = height. each slice is a right triangle with base = height Represent the volume of this solid as a definite integral. b a Type 3.14 for "pi" A solid is formed between x) and the x-axis so each slice (perpendicular to the x-axis) is a square. each slice is a square Represent the volume of this solid as a definite integral. 1') a. Type 3.14 for "pi" Top: y=f(x) Bottom: y=g(x) , mm \"WI The region between x) and g(x) is rotated around the x-axis to form a solid. Each slice (perpendicular to the x-axis) is an annulus (the region between 2 circles). Represent the volume of this solid as a definite integral. 1) a Type 3.14 for "pi" Let R be the region bounded by a: = 5, y = 3a: 2, y = 5:1: + 30. To find the volume of the solid when R is revolved around the m-axis, evaluate the integral E] f -x C] The volume of the solid formed when R is revolved around the x-axis is (Type "pi" to enter it) 1 3(8 m) and a: = 5 is revolved about the x-axis. Round your answer to four decimal places. :1 Find the volume of the solid generated when the region bounded by g = , y = 0 , a: = 1 , Suppose that R is the finite region bounded by y = 9:, y = a: + 5, a: = 0, and a: = 1. Find the exact value of the volume of the object we obtain when rotating R about the :c-axis
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