Please help answer missing blanks (parts 3-6) thank you :)

12:19 a.m. Mar mar. 1 moer.maricopa.edu 75% A military artillery shell is fired horizontally from the roof of a skyscraper. The artillery shell leaves the edge of the skyscraper with a velocity of magnitude 7.6 m/s. After 1.9 s, determine the artillery shell's (a) and (c) velocity. horizontal distance from the edge of the skyscraper and (b) vertical distance from the top of the skyscraper, 1. What is the initial instant described in the paragraph above? The instant immediately after the shell is fired ) of 2. What is the final instant described in the paragraph above? An instant 1.9 seconds after the initial instant when the shell is in midair 3. Outline the information given in the paragraph above by finding the value for each quantity in the table below. Do not attempt to solve for any of these expressions. The purpose of this table is simply to summarize the information given in the paragraph above. In addition, use the pull down menus to describe the sign of each quantity. Notes: a. Enter the letters 'DNE for any quantity whose value is not given in the problem statement above. b. Be aware that you do not need a calculator to complete this question. You can type in expressions such as 3*9.8 or 5 cos () c. Be aware that trig functions expect angles to be expressed in radians. To enter a trig function for an angle in degrees, multiply the angle by 180 . For example, the cosine of 40 may be entered as cos ( 40 - 180 . Type 'pi' to enter T. Horizontal Direction Vertical Direction Value Sign Value Sign Positive C ) Negative m m Ax Positive m m Zero C Vo S Negative C Positive C m Uf S Negative m m Zero 2 a 2 Positive At 4. After 1.9 s, determine the artillery shell's horizontal distance from the edge of the skyscraper. m Distance from the edge of the skyscraper = 5. After 1.9 s, determine the artillery shell's vertical distance from the top of the skyscaper. m Distance from the top of the skyscraper' = 6. After %dt s, determine the magnitude and direction of the artillery shell's velocity. m Magnitude of of = Select an answer Direction of Uf =