Question: Please help answer my question! It will be greatly appreciated! Estimated line: y = 0 . 5 x 0 . 9 5 Actual line: y

 Please help answer my question! It will be greatly appreciated!Estimated line:

Please help answer my question! It will be greatly appreciated!

Estimated line: y=0.5x0.95

Actual line:y=0.65x0.705

To see how close the tangent line (call it the "estimated line") is to the actual tangent line ("actual line"), calculate the percent difference (i.e., error) between the slopes of the two lines and between they-intercepts of the two lines, as follows (please show work).Note the absolute values in the numerator and denominatorround answers to 2 decimal places.

y=0.5x0.95Actual line:y=0.65x0.705To see how close the tangent line (call it the "estimated

|slope of actual line - slope of estimated line] % error in slopes = X 100 = 0% |slope of actual line | ly intercept of actual line - y intercept of estimated line| % error in y intercepts = X 100 = % ly intercept of actual line| Average of the two percentage errors calculated above: %

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