Question: please help ASAP In a queueing system, customers arrive once every 3 minutes (standard deviation = 4) and services take 2 minutes (standard deviation =

please help ASAP In a queueing system, customers please help ASAP

In a queueing system, customers arrive once every 3 minutes (standard deviation = 4) and services take 2 minutes (standard deviation = 6.3). (Do not round intermediate calculations. Round your answer to three decimal places.) What is the average time a customer will spend in the queue (in minutes)? 1.000 X minutes

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