Please help!

Consider a triangle ABC like the one below. Suppose that a = 45, b =$1, and A =40. (The figure is not drawn to scale.) Solve the triangle. Carry your intermediate computations to at least four decimal places, and round your answers to the nearest tenth. If no such triangle exists, enter "No solution." If there is more than one solution, use the button labeled "or". by B - - c- [. c-0 No solution XTo minimize rounding error, we found c using a and A (wh Here is the answer, with values rounded to the nearest ten ANSWER B =46.8 , C=93.2" , c=69.9 , or B = 133.20 , C=6.89 , c= 8.2> Given that, a= 45, 6: 51 and A= 40 we know, the sine rule is a C Sin(A) Sin (B ) Sin (c ) Now, taking first teso of equ " we get- a b Sin ( A) Sin (B) 45 - 51 Sin (40 )' Zin (B ) 7) Sin (B ) = 51 x Sin (40) 45 2 ) Lin (B ) = 51 x 0 . 6428 45 2 0 . 7285 2 ) B= Sin (0.7285 ) 2 B = 46 . 75 24 133- 24750 2 ) B ~ 46 . 8 133 . 20 we know, the sumof three angle of a triangle is 180" 20, if / B = 46- 8" then