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Equations & Constants 1 cm3 = 1 mL Trig Functions: 60 s = 1 min 2.54 cm = 1 inch Acceleration due to Gravity: sin 0 = opposite 60 min = 1 hr 12 inches = 1 ft dy = -g= -9.81 m/s2 cos ! = hypotenuse 3 ft = 1 yrd tan 0 = opposite adjacent Kinematics Displacement: Constant Acceleration in x: Constant Acceleration in y: Ax = x1 - Ti Unf = Uri + art Wyf = Vyi + aut Constant Velocity: Ar = 3(Uri + Uif)t Ay = 2(Uyi + Wyf) t = vi = Uf At = Unit + jazt2 Ay = Unit + zayt2 Ax = vt Uuf = Uni + 2ay Ay Forces Newton's Laws: Weight: Friction: CF =0 - a=ol F, = mg osf. Sus FN EF = ma Centripetal Acceleration: fr = HKEN F2on1 = -Flon2 de = 02/ R Hooke's Law: F, = -k(AT) Energy Types of Energy: KE = my2 Work: PE, = mgh Work Energy Theorems: W = F . AT PE, = }k(4x)2 EW tot = AKE (W = FAx cose Etot = KE + PE, + PE, EW. = -APE AEtot = AKE + APE, + APE, EW nc = Etot P = AEtot/ At 6. (10 pts) In lab you shot a projectile off of the edge of a table at an angle of 30 with a 8. (4 pts) A block that weighs 60 N is initially at rest on a horizontal surface. A horizontal speed of 2.5 m/s. It landed 1.5 m away from a point directly below the launch position. force Fi of magnitude 22 N and a vertical force F2 are then applied to the block. The How high up off the ground was the projectile launched? coefficients of friction for the block and the surface are /s = 0.50 and uk = 0.25. Determine the magnitude of the frictional force acting on the block if the magnitude of F2 is (a) 10 N, (b) 20 N vo = 2.5 m/s 30 4y Ax 9. (4 pts) A toy airplane with a mass of exactly 0.200 kg is tied to a 1.50 m string. The other end of the string is attached to the ceiling. The toy airplane is moving in a horizontal circle with a constant speed, v. The angle 0 between the string and the vertical direction is 30.0. (a) What is the tension in the string? (b) Given that this is Uniform Circular 7. (4 pts) Three boxes with mass M1, M2, and My are connected by massless, inextensible Motion, find the tangential velocity of the toy airplane, v. strings which pass over massless, frictionless pulleys. Draw FBDs for all three boxes and write out Newton's Second Law. No need to solve anything here! T2 M2 No Friction. Mg