Please help me answer the following question (c) A previous study found that 15% of nurses reported participating in mental health support programs. From the 96% found in (b) , can you conclude that proportion of nurses reported participating in mental health support programs p(current), has changed from the previous study? (Yes/No) because the confidence interval in (b) (captures/does not capture) 15%. (d) Refer to your answer in (b) : The Alberta Nurses Association expects that not more than 23 % of nurses will participate in the survey on mental health support programs. Given the result in part (b) can we conclude that this expectation is reasonable? (Yes/No) because the (upper bound/lower bound) of the 96% confidence interval is (less thanot less than/greater than) 23%.

The Alberta Nursing Association conducts an annual survey to estimate the proportion of nurses who participate in mental health support programs.

The most recent application of this survey involved a random sample of n=475 nurses across Alberta. Each participant was asked about their participation in mental health support programs in this year.

The number of nurses sampled who reported participating in a mental health support program in this year is 83 .

(a) Compute the sample proportion. Use at least four decimals in your answer.

widehat(p)=

(b) Using your answer in (a), find a 96% confidence interval for p_("current "), the proportion of nurses who participate in mental health support programs,

To avoid rounding errors you should use R-Studio and copy and paste options(digits=10) to the R console before calling other R codes

Use at least four decimals in all your calculations.

lower bound =

upper bound =

(c) A previous study found that 15% of nurses reported participating in mental health support programs.

From the 96% found in (b), can you conclude that proportion of nurses reported participating in mental health support programs p_("current "), has changed from the previous study?

because the confidence interval in (b)

15%.

expectation is reasonable?

because the

of the 96% confidence interval is

23%.

The Alberta Nursing Association conducts an annual survey to estimate the proportion of nurses who participate in mental health support programs. The most recent application of this survey involved a random sample of m = 475 nurses across Alberta. Each participant was asked about their participation in mental health support programs in this year. The number of nurses sampled who reported participating in a mental health support program in this year is 83. (a) Compute the sample proportion. Use at least four decimals in your answer. e-( (b) Using your answer in (a), find a 96% confidence interval for Peurrent. the proportion of nurses who participate in mental health support programs, To avoid rounding errors you should use R-Studio and copy and paste options(digits=10) to the R console before calling other R codes Use at least four decimals in all your calculations. {c) A previous study found that 15% of nurses reported participating in mental health support programs. From the 96% found in (b) , can you conclude that proportion of nurses reported participating in mental health support programs Peurrent. has changed from the previous study? ? w~ because the confidence interval in (bb) ? w | 15%, (d) Refer to your answer in (b) : The Alberta Nurses Association expects that not more than 23 % of nurses will participate in the survey on mental health support programs. Given the result in part (b) can we conclude that this expectation is reasonable? ? 0 os becausethe 3 w~ of the 96% confidence interval is) 7 w | 23%