Question: **** please help me complete it *** // There are 2 parts in this program. /// Part 1: Reverse the linked list /// Part 2:

**** please help me complete it *** // There are 2 parts in this program.

/// Part 1: Reverse the linked list

/// Part 2: Parse string and display tokens.

/// Two types of tokens:

//// (1) a string without any blank, or

/// (2) a string with blanks in it, which is delimited by double quotes

#include

using namespace std;

struct Rectangle { int height; int width; };

struct ListNode { Rectangle rect; ListNode *next = nullptr; ListNode(int h, int w) { /// TO DO: Add your code here rect.height = h; rect.width = w; }; };

void display(ListNode* head) { /// TO DO: Add your code here ListNode *p = head;

while (p != NULL) { cout << "("; cout << p->rect.height << ", "; cout << p->rect.width << ")->";

p = p->next; if (p == NULL) { cout << "@"; } } cout << endl;

}

/// Reverse the nodes in the list void reverseLL(ListNode* &head) { /// TO Do: Add your code here return; }

int main() { /// Part 1

ListNode node1(1, 1); ListNode node2(2, 2); ListNode node3(3, 3); ListNode node4(4, 4); ListNode node5(5, 5); ListNode node6(6, 6); ListNode node7(7, 7);

node1.next = &node2; node2.next = &node3; node3.next = &node4; node4.next = &node5; node5.next = &node6; node6.next = &node7;

ListNode *head = &node1; /// Display the the list /// (1, 1)->(2, 2)->(3, 3)->(4, 4)->(5, 5)->(6, 6)->(7, 7)->@ display(head);

reverseLL(head); /// Display the the list /// (7, 7)->(6, 6)->(5, 5)->(4, 4)->(3, 3)->(2, 2)->(1, 1)->@ display(head);

node5.next = nullptr; reverseLL(head); /// Display the the list /// (5, 5)->(6, 6)->(7, 7)->@ display(head);

node6.next = nullptr; reverseLL(head); /// Display the the list /// (6, 6)->(5, 5)->@ display(head);

node6.next = nullptr; reverseLL(head); /// Display the the list /// (6, 6)->@ display(head);

/* Part 2: Uncomment this block of code

parseString(" ABC \"D. Trump\" E "); /// The function parse() will display /// ABC /// D. Trump /// E

/// You get extra 10% if the following function works.

parseString(" ABC E \"Big Data\" 1234 \"Donald John Trump\" ");

/// The function parse() will display

/// ABC

/// E

/// Big Data

/// 1234

/// Donald John Trump */ return 0; }

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