please help me figure out this: it is returning $[],$ when get$\_$nth$\_$key shows visited nodes, but it shoudl return multiple values. pleaase help: def get$\_$nth$\_$key$($self$,$ n$)$:

if self.root is None:

return $-1$ # Tree is empty, so n is out of bounds

result, node, visited $=$ self.$\_$get$\_$nth$\_$key$\_$helper$($self$.$root, n$)$

# Now 'visited' contains the list of visited node keys

# Here, you could potentially handle the 'visited' list depending on your requirement:

# For example, you could print it or check it against expected values in tests

print$("$Visited nodes:", visited$)$ # Example of usage

return result if node else $-1$ # Return $-1$ if the node is None $($n is out of bounds$)$

def $\_$get$\_$nth$\_$key$\_$helper$($self$,$ node, n$,$ visited$=$None$)$:

if visited is None:

visited $=[]$

if not node:

print$("$Reached a None node, returning."$)$ # Debug

return None,None,visited

left$\_$size $=$ node.left.subtree$\_$key$\_$count if node.left else $0$

right$\_$size $=$ node.right.subtree$\_$key$\_$count if node.right else $0$

print$($f$"$Visiting node $\{$node$.$key$\}$ with left$\_$size $\{$left$\_$size$\},$ right$\_$size $\{$right$\_$size$\},$ searching for index $\{$n$\}")$ # Debug

# Add the current node key to the visited list

visited.append$($node$.$key$)$

if n $<$ left$\_$size:

return self.$\_$get$\_$nth$\_$key$\_$helper$($node$.$left, n$,$ visited$)$

elif n $==$ left$\_$size:

return node.key,node,visited

else:

return self.$\_$get$\_$nth$\_$key$\_$helper$($node$.$right, n $-$ left$\_$size $-1,$ visited$)$