Question: please help me i am lost in all this The number of cell phones per 100 residents in countries in Europe is given in table

please help me i am lost in all this

The number of cell phones per 100 residents in countries in Europe is given in table #1 for the year 2010.The number of cell phones per 100 residents in countries of the Americas is given in table #2 also for the year 2010 ("Population reference bureau," 2013).

Table #1: Number of Cell Phones per 100 Residents in Europe

100 76 100 130 75 84

112 84 138 133 118 134

126 188 129 93 64 128

124 122 109 121 127 152

96 63 99 95 151 147

123 95 67 67 118 125

110 115 140 115 141 77

98 102 102 112 118 118

54 23 121 126 47

Table #2: Number of Cell Phones per 100 Residents in the Americas

158 117 106 159 53 50

78 66 88 92 42 3

150 72 86 113 50 58

70 109 37 32 85 101

75 69 55 115 95 73

86 157 100 119 81 113

87 105 96

Is there enough evidence to show that the mean number of cell phones in countries of Europe is more than in countries of the Americas?Test at the 1% level.

1= mean number of cell phones per 100 residents in countries of Europe.2= mean number of cell phones per 100 residents in countries of the Americas.Which of the following statements correctly defines the null hypothesisHO?

A.1+ 2= 0

B.1- 2< 0(1<2)

C.1 2> 0(1> 2)

D.12=0(1=2)

1= mean number of cell phones per 100 residents in countries of Europe. 2= mean number of cell phones per 100 residents in countries of the Americas.Which of the following statements correctly defines the alternate hypothesisHA?

A.1 2>0(1> 2)

B.1- 2< 0(1<2)

C.1 2=0(1= 2)

D.1+ 2= 0

What is the level of significanceused:

in decimal form.Examples:0.010.020.050.10

(iv)Forsamplefrompopulationwithmean=1:

Determinesamplemeanx1andsamplestandarddeviations1

Enter sample mean in decimal form to nearest hundredth, then comma, then sample standard deviation in decimal form to nearest hundredth.Examples of correctly entered answers:

13.20,2.34

0.27,0.06

-10.31,0.07

(v)Forsamplefrompopulationwithmean=2:

Determinesamplemeanx2andsamplestandarddeviations2

Enter sample mean in decimal form to nearest hundredth, then comma, then sample standard deviation in decimal form to nearest hundredth.Examples of correctly entered answers:

13.20,2.34

0.27,0.06

-10.31,0.07

what is the degrees of freedomdf:

Enter value in decimal form rounded down to nearest whole number.Examples of correctly entered answers:

2316110

what is the test statistic:

Enter value in decimal form rounded to nearest thousandth.Examples: 0.0143.03716.500110.081

Using tables, calculator, or spreadsheet:what is the p-value corresponding to test statistic.

Enter value in decimal form rounded to nearest ten-thousandth.Examples: 0.00010.00210.03050.60040.81431.0000

(ix)Comparing p-value andvalue, which is the correct decision to make for this hypothesis test?

A.AcceptHo

B.Fail to rejectHo

C.RejectHo

D.AcceptHA

(x)Select the statement that most correctly interprets the result of this test:

A.The result is not statistically significant at .01 level of significance.Sufficient evidence exists to support the claim that the mean number of cell phones in countries of Europe is more than in countries of the Americas.

B.The result is not statistically significant at .01 level of significance.There is not enough evidence to support the claim that the mean number of cell phones in countries of Europe is more than in countries of the Americas.

C.The result is statistically significant at .01 level of significance.Sufficient evidence exists to support the claim that the mean number of cell phones in countries of Europe is more than in countries of the Americas.

D.The result is statistically significant at .01 level of significance.There is not enough evidence to support the claim that the mean number of cell phones in countries of Europe is more than in countries of the Americas.

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