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8:35 '1 II\" LTE C} Take Quiz Exit D Question 12 Average Price of a Big Mac y = 0.0726): - 142.41 R1 = 0.8766 What type of linear correlation exists between years and price? 0 strong positive correlation 0 strong negative correlation 0 weak positive correlation 0 weak negative correlation D Question 13 Average Price of a Big Mac 5150 . ... 53 no ' _...--"'O" 51 50 51" 9 51.50 6""; y = 0.0725x - 142.41 51.00 R1 = 0.8766 8:35 4 .I LTE Take Quiz Exit Question 16 1 pts Average Price of a Big Mac $4.00 $3.50 $3.00 $2.50 $2.00 $1.50 y = 0.0726x - 142.41 $1.00 R2 = 0.8766 $0.50 1986 1991 1996 2001 2006 2011 How many years of actual data did we collect? Question 17 1 pts Average Price of a Big Mac $4.00 $3.50 $3.00 $2.50 $2.00 $1.50 y = 0.0726x - 142.41 $1.0 R2 = 0.8766 $0.50 1986 1991 1996 2001 2006 2011 If we were to use this model to predict the a Rio8:35 '7 II\" LTE C} Take Quiz Exit LUIICLLI Average Price of a Big Mal: y = 0.0726): - 142.41 R: = 0.8766 1396 2001 2005 If we were to use this model to predict the cost of a Big Mac in 2025, how many years into the future would the model be predicting? Average Price of a Big Mac 8:35 '7 II\" LTE C} Take Quiz Exit D Question 18 Average Price of a Big Mac . .,...........,.t... ' . y = 0.0726): - 142.41 R1 = 0.8766 1991 1996 20M EDGE Should we use this model to predict the price of a Big Mac in 2025? Why or why not? You will hand in your explanation for grading by hand. 0 Select this if you said yes, no, or maybe 0 I do not know No new data to save. Last checked at 8:35am Submit Quiz ime Elapsed: Hide ttempt due: Apr 4 at 1b 8:35 '1 III LTE [:1' Take Quiz Exit D Question 11 Average Price of a Big Mac . ...'..l....-.......... . y = 0.0726): - 142.41 R3 = 0.8766 5 . 1N6 1991 1396 M1 Interpret the meaning of the slope. O The average price of a Big Mac increases by 350.0726 every year 0 0.0726 Big Macs are sold per person in the United States 0 142 less Big Macs are sold very year Q The average price of a Big Mac increases by $03766 per year. D Question 12 $150 $300 51 so 52.00 51.50 v = 0.0726: - 142.41