Question: Please help me only if you really know how to solve it as I am stuck and I cannot solve these questions. Dont give me

 Please help me only if you really know how to solve

Please help me only if you really know how to solve it as I am stuck and I cannot solve these questions. Dont give me random answers please. You can use any software to solve it if it's easier ( we use R). If I am satisfied, i will also make sure you are satisfied too.

Link to textbook if needed with the content: https://drive.google.com/file/d/1ptM7Pzw8e364cZpwdQXU30GVhrQc1AZ7/view?usp=sharing

Questions:

it as I am stuck and I cannot solve these questions. Dontgive me random answers please. You can use any software to solveit if it's easier ( we use R). If I am satisfied,

Question Researchers wish to carry out a test of the null hypothesis that the mean of a certain population is 70 against a two-sided alternative hypothesis. In their situation, they (somehow) happen to know the population standard deviation. They feel comfortable assuming normality for this population, and carry out a 2 test. They draw a sample of 36 individuals from this population, and find a 2 test statistic of 0.35. What is the p-value of the test? (Give your numeric response to at least 3 decimal places. Give only your numeric response, and not any extra characters or symbols.) Your Answer: a . Your Answer Question Researchers wished to investigate possible effects of an antivenom on swelling. 16 pigs were randomly assigned to an antivenom group or a control group [3 pigs to each group). All pigs were then subjected to a dose of snake venom, and either a dose of antivenom or a saline control. The researchers then measured the increase in leg volume (mL) after 8 hours as their measure of swelling. They carried out the pooled-variance t procedure in R, with the following results. Two Sample t-test data: antivenom_swelling and control_swelling t = 0.068927, df = 14, p-value = 0.946 alternative hypothesis: true difference in means is not equal to 0 95 percent confidence interval: -94.11511 100.36511 sample estimates: mean of x mean of y 203.750 200.625 Of the following options, which one is the best conclusion to that hypothesis test? ("3, There is no evidence that the antivenom treatment and the control treatment ' have different sample mean swelling. ("'3 There is no evidence that the antivenom treatment and the control treatment J have different true mean swelling. (\""1 There is very strong evidence that the treatment and control have the same H effect on swelling. (\"3, There is very strong evidence that the antivenom treatment and the control \\. ' treatment result in exactly the same true mean swelling. Question Consider the following output for a one-sample procedure from R's t.test. One Sample t-test data: data t = 4.1894, df = 49, p-value = 0.0001162 alternative hypothesis: true mean is not equal to 15 95 percent confidence interval: 16.61141 19.58255 sample estimates: mean of x 18.09698 Which of the following statements are true? There may be more than one correct statement; check all that are true. [_] a) There is strong evidence that the true mean is greater than 15. Cl bl The p-value is double the area to the right of 4.1894 under a t distribution with 49 degrees of freedom. [_] c) One way to express the null hypothesis used in this test isHU : X = 15. l:' d) There must be an error in the output, since the sample mean should not lie within the confidence interval

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