Question: Please help me only if you really know how to solve it as I am stuck and I cannot solve these questions. Dont give me

 Please help me only if you really know how to solve

Please help me only if you really know how to solve it as I am stuck and I cannot solve these questions. Dont give me random answers please. You can use any software to solve it if it's easier ( we use R). If I am satisfied, i will also make sure you are satisfied too.

Link to textbook if needed with the content: https://drive.google.com/file/d/1ptM7Pzw8e364cZpwdQXU30GVhrQc1AZ7/view?usp=sharing

Questions:

it as I am stuck and I cannot solve these questions. Dontgive me random answers please. You can use any software to solve

Question : Suppose we are about to carry out 88 independent hypothesis tests. We intend to carry out each test at a significance level of 0.05. Suppose that the assumptions of each test are true, and, unknown to us, the null hypothesis is true in all 88 situations. What is the probability that we make a Type I error in exactly 10 of the 83 tests? (Give your numeric response to at least 3 decimal places. Give only your numeric response, and not any extra characters or symbols.) Your Answer: . . Your Answer Question Consider the following output from R's t.test. Welch Two Sample t-test data: Groupl and Group2 t = 3.293, df = 96.94, p-value = 0.001384 alternative hypothesis: true difference in means is not equal to 0 95 percent confidence interval: 0.2236737 0.9023599 sample estimates: mean of x mean of y 0.60187433 0.03885753 Which of the following statements are true? There may be more than one correct statement; check all that are true. l._.' a} The p-value is small. so there is no evidence of a difference in population means. l:' b) The p-value in the output is double the area to the left of 3.293 under a t distribution with 96.94 degrees of freedom. Cl c) One way to express the null hypothesis used in this test ing : X1 = XE. [_] d) The evidence against the null hypothesis is statistically significant at the 5% significance level

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