Please help me out.. A and C

Question. 5. (30 points) Consider a computer with byte addressable main memory bytes, and the block size is 8 bytes. Assume that a direct mapping cache consisting 32 lines is used with this machine. (a) (5 points) How many bits are required to hold a memory address? (b) (5 points) How many total bytes of memory can be stored in the cache? 256 bytes (C) (10 points) How is that memory address divided into tag, line number, and byte (word) fields? (d) (10 points) Into what line would the data having following memory addresses be stored? . 0001 0001 0001 1011 as the cache line part is oooll, its decimal is encivalent is 3 1100 0011 0011 0100 As the cache line part is Gollo, its decima is caninant is 6 1101 0000 0001 1101 As the cache line part is oooll, its dea equivalat is 3 . 1010 1010 1010 1010 As the cache line part is 10101, dumal is equivalent is 21