Question: Please help me solve this statistics problem Interferences about the population Show all work please. 3. [40 POINTS=5+10+5+10+101 A STUDY OF THE VARIANCE IN STUDENTS'
Please help me solve this statistics problem
Interferences about the population
Show all work please.

3. [40 POINTS=5+10+5+10+101 A STUDY OF THE VARIANCE IN STUDENTS' MONTHLY EXPENSES WAS CONDUCTED. ASSUME THAT FOR A RANDOM LY SELECTED STUDENT, THE AMOUNT SPENT PER MONTH IS NORMALLY DISTRIBUTED WITH UNKNOWN PARAMETERS. A SAMPLE OF 16 STUDENTS WAS SELECTED WITH THE SAMPLE SUMMARIES AS FOLLOWS: (SAMPLE MEAN) = $1,350 AND (SAMPLE STANDARD DEVIATION) = $13. (A) (B) (C) (D) (E) AT THE 1% SIGNIFICANCE LEVEL, DO RESEARCHERS HAVE EVIDENCE THAT THE POPULATION VARIANCE WAS BELOW 900? CIRCLE APPROPRIATE ANSWER: YES! NO! SPECIFY THE TEST STATISTIC VALUE, CRITICAL VALUE, AND TEST STATISTIC VALUE. THEN FORMULATE THE REJECI'ION RULE. TEST STATISTIC VALUE = CRITICAL VALUE(S): REJECPION RULE STATES... AT THE 1% SIGNIFICANCE LEVEL, CAN RESEARCHERS STATE THAT THE POPULATION VARIANCE WAS ABOVE 160? CIRCLE APPROPRIATE ANSWER: YES! NO! SPECIFY THE TEST STATISTIC VALUE, CRITICAL VALUE, AND TEST STATISTIC VALUE. THEN FORMULATE THE REJECTION RULE. TEST STATISTIC VALUE = CRITICAL VALUE(S): REJECI'ION RULE STATES... ESTIMATE THE POPULATION VARIANCE WITH THE 95% CONFIDENCE (ROUND OFF THE ANSWERS TO THE 2\"\" DECIMAL PLACE). SPECIFY THE CRITICAL VALUES NEEDED FOR THIS PROCEDURE. UPPER CONFIDENCE LIMIT = CRITICAL VALU E = LOWER CONFIDENCE LIMIT = CRITICAL VALUE =
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