Please help me with this assembly code. So in this code I need to print my eax. but in the debugger it always say segmentation fault. And my prof says in line $28$ my mov $$1,\%$edx is right, but i also need to move dx to a memory location, then move the mem loc to ecx. so what memory location should i use?.

$.$data

$.$equ STDIN, $0$

$.$equ STDOUT, $1$

$.$equ READ, $3$

$.$equ WRITE, $4$

$.$equ EXIT, $1$

$.$equ SUCCESS, $0$

$.$text

$.$global $\_$start

#subroutine to print a number

print$\_$number:

xor $\%$ecx, $\%$ecx #counter for the number of digits

calculate$\_$digits:

movl $$0,\%$edx #clear before division

movl $$10,\%$ebx

div $\%$ebx #eax$/$ebx$,$ quotient in eax, remainer in edx

add $$\text{'}0\text{'},\%$dl #convert digit to ASCII

push $\%$dx #push ASCII digit into stacks

inc $\%$ecx #increment counter

cmp $$0,\%$eax #check if quotient is zero

jne calculate$\_$digits #if eax is not zero, continue calculation

print$\_$digits:

movl $\%$ecx, $\%$ebx #save counter value

print$\_$loop:

pop $\%$dx #pop digit from stack

mov $\%$dl$,\%$al #move digit to al for printing

movl $$1,\%$edx #length of $1$

movl $STDOUT, $\%$ebx #file descriptor

movl $WRITE, $\%$eax #system calL

int $$0$x$80$ #call kernel

dec $\%$ecx #decrement counter

jmp print$\_$loop #if counter is not zero, print next digit

ret #return from the subroutine

$\_$start:

#test$1$

movl $$12345,\%$eax #put the nuber to be printed

call print$\_$number #call the subroutine

#test$2$

movl $$67890,\%$eax #put the number to be printed

call print$\_$number #call the subroutine

done:

movl $EXIT, $\%$eax

movl $SUCCESS, $\%$ebx

int $$0$x$80$