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Example 4 Solution: Find the perimeter of a wall whose length is 250 m and the diagonal is 370 m. Solution: 3702 = x2 + 2502 Apply the Pythagorean Theorem 136,900 = x2 + 62,500 X 370in 136,900 - 62,500 = x2 APE 74,400 = x2 Solve the quadratic equation by extracting the square root 250m 272.76 m = x The width measures 272.76 meters To solve for the perimeter of the wall, we need to get the distance around the wall. P =1+1+w+w P - 21 + 2w P = 2(250) + 2(272.76) P = 1045.52 The perimeter of the wall is 1045.52 meters Practical Application: Solve each problem. 1. A 12-meter fire truck ladder leaning on a vertical fence also leans on the vertical wall of a burning three-storey building. The distance of the wall to the base of the ladder is 5 meter. How high does the ladder reach? 2. A 13-ft ladder is leaning against a 9ft-wall. What is the distance of the base of the ladder to the wall? 3. A working student has to deliver a package to a client. Before he can reach the client's office, he has to travel 3 km due east, then 4 km due south. How far is his office from the client's office Refer to the following figures and find the length of the specified segment. 5. 6. 9 18 C y 60 12 7 8. 9 32 m W 9V3 24 60 45% 10. 450 10 45