Question: please help me with this Question the original Question is in German language but I translate it to English I will also provide some example

please help me with this Question

the original Question is in German language but I translate it to English I will also provide some example may help you understand the Question

please help me with this Questionthe original Question is in German languagebut I translate it to English I will also provide some example

Exercise 6 (analysis and mean values) in an analytical laboratory, the sugar content of a product is determined using different measuring methods. In order to be able to compare the different mean values, they hay_e____tg be calculated. The reference examination delivers the following values: Mass 5,2 4,5 5,2 4,7 5,8 4,7 4,7 5,2 5,8 4,7 in mg a) Calculate the average mass as number mean, mass mean and centrifuge mean. b) Calculate the distribution width (polydispersity index PDi). c) Sketch the distribution in a suitable graphic representation and mark the numerical mean, mass mean and centrifuge mean in each case. Example with answer : may help you Mean values - Example Steinhaufen: 20 Steine 1 kg 50 Steine 2 kg 70 Steine 3 kg 40 Steine 4 kg 10 Steine 5 kg 5 Steine 6 kg Task: Calculate number averages, mass averages and centrifuge means_as well as PDI Zahlenmittel Massenmittel Zentrifugenmittel M - Zn; . M, M. = -En, . M,' En; . M. En, . M Polydispersitatsindex PDI = U +1=4x German language ..English translate Steinhaufen = stones Mean values - Example Steinhaufen: 20 Steine 1 kg 50 Steine 2 kg 70 Steine 3 kg 40 Steine 4 kg 10 Steine 5 kg 5 Steine 6 kg M _ 20'1+50*2+70*3+40*4+10*5+5*6_570 , 20+50+70+40+10+5 195 M. = 20*12 +50*2" +70*3" +40*42 +10*52 +5*62 1920 20*1+50*2+70*3+40*4+10*5+5*10 570 -=3.37 7200 1090 = 3.75 1920 Haufigkell PDI = M. _3,37 M. 2.92 - =1,15 Polymercharakterisierung Masse (kg) TUG Task 1: The fuel consumption of two cars of type A and B was tested. The following values n liters / 100 km were measured: Typ A 5,1 4,7 5,8 5,1 4,9 5,1 4,7 4,7 4,9 5,1 Typ B 5,8 4,7 5,2 4,7 4,7 4,7 4,5 5,2 5,8 5,2 "(Ctrl) . ) Calculate the average consumption for each vehicle type as number average, mass average and centrifuge average. b) Calculate the distribution width (polydispersity index PDI). c) Sketch the distribution and mark the numerical mean, mass mean and centrifuge mean in each case. Answer: "(Ctrl) meaning Zahlenmittel Numerical mean En, .M, = 5,01 or. 5,05 L / 100 km Massenmittel -> Mass means M. = 5,03 or. 5,08 L / 100 km "(Ctrl) * Zentrifugenmittel Centrifuge means M. = En, . M. = 5,05 or. 5,13 L / 100 km Polydispersitatsindex PDI = U +1= = 1,004 or. 1,006 "(Ctrl) . "(Ctrl)

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