Please help solve Part B only my answer for part A was "0.15 m/s"

ube Maps UD UHD Zoom MD Anderson | Harris County Publ... SALE-Not Your Ave... KPRC 2 Community.. @ HISTOLOGY GUIDE Qu TACTICS BOX 14.1 Identifying and analyzing simple harmonic motion Learning Goal: 1. If the net force acting on a particle is a linear restoring force, the motion will To practice Tactics Box 14.1 Identifying and be simple harmonic motion around the equilibrium position. analyzing simple harmonic motion. 2. The position, velocity, and acceleration as a function of time are given in A complete description of simple harmonic motion Synthesis 14.1 (Page) : must take into account several physical quantities x(t) = A cos(27 ft), and various mathematical relations among them. This Tactics Box summarizes the essential UI(t) = -(27 f) A sin(27 ft), information needed to solve oscillation problems of az (t) = -(27 f)2 A cos(27 ft). this type. The equations are given here in terms of x, but they can be written in terms of y, or some other variable if the situation calls for it. Tool 0 X 3. The amplitude A is the maximum value of the displacement from equilibrium. The maximum speed and the maximum magnitude of the acceleration are QV Q V . . . given in Synthesis 14.1 (Page) : Vmax = 27 f A and amax = (27 f)2 A, respectively. 4. The frequency f (and hence the period T = 1/ f) depends on the physical properties of the particular oscillator, but f does not depend on A. For a Part B mass on a spring, the frequency is given by Assume that the oscillating mass described in Part A is attached to a spring. What would the spring constant k of this spring be? K Express your answer in newtons per meter to two significant figures. 2TV View Available Hint('s) 5. The sum of potential energy plus kinetic energy is constant. As the oscillation proceeds, energy is transformed from kinetic into potential energy and then back again. N/m Part A Submit V The position of a 40 g oscillating mass is given by x (t) - (2.0 cm) cos(10t), where t A is in seconds. Determine the velocity at t - 0.40 s