Question: Please help to answer #1, #3 CHECK Your Understanding 1. Simplify. State any restrictions on the variables. N a) c ) ( x + 1

Please help to answer #1, #3

Please help to answer #1, #3 CHECK Your Understanding 1. Simplify. Stateany restrictions on the variables. N a) c ) ( x +1 ) ( x - 5 ) ( x + 4 )

CHECK Your Understanding 1. Simplify. State any restrictions on the variables. N a) c ) ( x + 1 ) ( x - 5 ) ( x + 4 ) 3 X (x + 4) 2 (x - 5) b ) 6xy 4- 2 X 6x + 3 573 8 d) X 2x + 1 5x 2. Simplify: State any restrictions on the variables. 2x a) 3x(x - 6) C) (x - 6) 3 5 (x + 2) (x - 7 ) (x + 2 ) x - 7 2x - 14 x 2 b ) d) x+1 10 25 x - 2 12 - 6x 3. Simplify. State any restrictions on the variables. ( x + 1 )2 (x - 1) a) X H x2 + 2x - 3 x2 + 4x + 3 2x + 10 x 2 - 25 b) x2 - 4x + 4 x - 22ab2 14a2 5. Simplify. State any restrictions on the variables. a) 2 (x + 1 ) X x - 1 3 c ) 2 ( x - 2 ) 12x4 6(x + 1) 9x3 X 2 - x b ) 3a - 6 a- 2 at 2 at2 d) 3 (m + 4) 2 5(m + 4) 2m + 1 7m + 14 6. Simplify. State any restrictions on the variables. a) (x + 1) (x- 3) X 2 (x + 2) ( x + 2 ) 2 (x - 3) (x + 3) b) 2 (n - 7n + 12) 5(n - 4) n - n - 6 n2 - 4 2x - x - 1 C) 6x2 - 5x + 1 x2 - x - 6 X 8x2 + 14x + 5 d) 9y2 - 4 . 92 + 12y + 4 4y - 12 18 - 6y 7. Simplify. State any restrictions on the variables. H x2 - 5xy + 42 x2 + 2xy + yz a) X x2+ 3xy - 28y2 x 2 - yz 202 - 12ab + 1862 4a2 - 12ab b ) a2 - 7ab + 1062 a2 - 7 ab + 1062 10x2 + 3xy - y 6x2 + 3xy C) 9x2 - y 12x + 4y 15m + mn - 2n 7m' - 8mn + n2 d) X 2n - 14m 5m2+ 7mn + 2n2Open with 10. An object has mass m = P + 1 p - 1 3p + 1 and density P - 92 + 6p + 1 Determine its volume v, where p = -. State the restrictions on any variables. 11. Liz claims that if x = y, she can show that x + y = 0 by following these steps: T Since x = y, I squared both sides of the equation. So x2 - y = 0. I rearranged terms in the equation. x2 - y 0 x - y x - y I divided both sides by x - y. (x J ) ( x ty ) 0 I factored and simplified. x x ty = 0 Sarit says that's impossible because if x = 1, then y = 1, since x = y. Substituting into Liz's final equation, x + y = 0, gives 1 + 1 = 2, not 0. Explain the error in Liz's reasoning. 12. a) Why do you usually factor all numer

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