please help

To prevent shrinkage when a pivot is fitted into a steel hub, the pivot has to be cooled based to the equation below: f(Tp) = -0.50598x10-1077 +0.38292x10-';* + 0.74363x10-*T+ 0.88318x10^2 = 0 1.1. Use the Bisection method to find Tj; with the initial and final temperature Tri= -150C and T, = -100C, respectively, and a tolerance of le-10 = 1.2. Use the secant method to find Ty; with the initial and final temperature Tri = -150C and T, = -100C, respectively, and a tolerance of 1e-10