Question: Please help to solve with details using Central Ljmit theorem with p=0.15. 200 200- . 2 (2:0) p(1 p) '1 WIth p = 0.15 n=25

Please help to solve with details using Central Ljmit theorem with p=0.15.

Please help to solve with details using Central Ljmit theorem with p=0.15.

200 200- . 2 (2:0) p"(1 p) '1 WIth p = 0.15 n=25 Please use Central limit theorem (with steps) to approximate the above probability

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