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Use z scores to compare the given values. In a recent awards ceremony, the age of the winner for best actor was 38 and the age of the winner for best actress was 50. For all best actors, the mean age is 48.1 years and the standard deviation is 6.1 years. For all best actresses, the mean age is 38.3 years and the standard deviation is 10.6 years. (All ages are determined at the time of the awards ceremony.) Relative to their genders, who had the more extreme age when winning the award, the actor or the actress? Explain. Since the z score for the actor is z = | and the z score for the actress is z = ], the | had the more extreme age. (Round to two decimal places.)The accompanying data are lengths (inches) of bears. Find the percentile corresponding to 70.5 in. Click the icon to view the bear length data. The percentile corresponding to 70.5 in. is. (Round to the nearest whole number as needed.)Find the area of the shaded region. The graph depicts the standard normal distribution of bone density scores with mean 0 and standard deviation 1. z= -0.95 The area of the shaded region is. (Round to four decimal places as needed.)Find the area of the shaded region. The graph depicts the standard normal distribution of bone density scores with mean 0 and standard deviation 1. Z= - 0.98 2=1.24 The area of the shaded region is. (Round to four decimal places as needed.)