Please help with explaining things that are legible, Thank you

A cylinder (round can) has a circular base and a circular top with vertical sides in between. Letr

be the radius of the top of the can and leth

be the height.The surface area of the cylinder,A

, isA=2r

2+2rh (it's two circles for the top and bottom plus a rolled up rectangle for the side).

Part a: Assume that the height of your cylinder is6 inches.ConsiderA as a function ofr, so we can write that asA(r)=2r^2+12r

. What is the domain ofA(r)? In other words, for which values ofr isA(r) defined?

Part b: Continue to assume thatthe height of your cylinder is6 inches. Write the radiusr as a function ofA. This isthe inverse function toA(r)

, i.e to turnA as a function ofrinto.ras a function ofA

Hints:

To calculate an inverse function, you need to solve forr

Here you would start withA=2r^2+12r

This equationis the same as2r^2+12rA=0 which is a quadratic equation in the variabler, and you can solve that using the quadratic formula.

Part c: If the surface area is300 square inches, then what is the rardiusr? In other words, evaluater(300) Round your answer to 2 decimal places.

.