Please help with parts 7 (graph table 1 in excel) and 13 (Table 3: Voltage Drop)! Thank you for your time!

\fData Section Table 1. Current Data for Series Circuit Total Resistance of Circuit Measured current (mA) R1 = 470 47 0 0.03191489 mA R2 = 820 R1 + R2 = 470+ 820 =129 0 0.01162791 mA R3 = 1500 R1 + R2 + R3 = 470+ 820 +1500-279 0 0.005376344 mA R4 = 2200 R1 + R2 + R3 + R4 =470+ 820 +1500 +2200 = 499 0 0.003006012 mA R5 = 3300 R1 + R2 + R3 + R4 + R5 = 0.001809409 470+ 820 +1500+2200+3300 =829 0 mA Table 2. Current Data for Activity 2 circuit Section Measured current (mA) Left Loop 0.004297994 mA Right Loop 0.002669039 mA Bridge 0.003618818 mA Table 3. Voltage drop across each resistor in Activity 2 circuit Resistor Voltage Drop 470 820 1500 2200 33007. Graph the data (x = 1/R, y = /), and plot a linear regression through the points. The slope of this line should be V, the voltage of the battery.13. Using the current data and the voltage of the batteries, calculate the voltage drop across each resistor in the circuit and include in Data Table 3