Question: Please help with percent error thank you 18+ 15+ 16= 49 - 3 =16.333 . 1000 0 . 016 Liters Average of moles of Naott

Please help with percent error thank you

Please help with percent error thank you 18+ 15+
18+ 15+ 16= 49 - 3 =16.333 . 1000 0 . 016 Liters Average of moles of Naott 0 . 016 - 0.100 / = 1.4 Average of molarity of acetic acid 1.6 : 51 = 21.5 Average mass of acetic acid 6. 0 16 X 60. 1 1 = 0. 9614 %% (m / m) CH3 Coot in Vinegar 6. 61 - 5 = 1. 322 X 100 = 132.2 True mass fo acetic acid invinegar percent error = 0 of. error = [ . (m/m ) CH3 coott in vinegar - true mass of. aceticacid in vinegar ] = truemass) . acetic acid in vinegar

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