Please help with practice problem.

This problem is about evaluating the integral n 1 j; (1 _ x2)312 dx To start, one would make a suitable trigonometric substitution of x in terms of 6. : (b) Find a correct resulting 0 integral from the choices below, i.e. find a corresponding integral with respect to the variable 0 sec e de 0 de sec2 0 0 O sec e de sec- 0 do de sec- 0 V2/2 c) The value of 1 (1 - x2)3/2 dx =