Please help with the question below. (Thank you)

Under certain waterconditions, the free chlorine(hypochlorous acid,HOCl) in a swimming pool decomposes according to the law of uninhibited decay. After shocking apool, the poolboy, Geoff, tested the water and found the amount of free chlorine to be 2.7 parts per million (ppm). Twenty-four hourslater, Geoff tested the water again and found the amount of free chlorine to be 2.4 ppm. What will be the reading after 3 days(that is,72 hours)? When the chlorine level reaches 1.00 ppm, Geoff must shock the pool again. How long can Geoff go before he must shock the poolagain?

After 3 days, or 72 hours, the amount of free chlorine in the pool will be __________ ppm.

(round final answer by hundredth as needed)

Geoff will need to shock the pool again in_______ hours.

(round final answer by hundredth as needed)