Question: Please I need the correct answer to e. Thank you According to a certain organization, adults onKed an average of 1,803 hours last year. Assume
Please I need the correct answer to e. Thank you

According to a certain organization, adults onKed an average of 1,803 hours last year. Assume the population standard deviation is 380 hours and that a random sample of 50 adults was selected. Complete parts a through e below. u - Jud-r X (Round to two decimal places as needed.) b. What is the probability that the sample mean will be more than 1,810 hours? P(i>1,810) = 0.4432 (Round to four decimal places as needed.) c. What is the probability that the sample mean will be between 1,770 and 1,790 hours? P (1 ,770 s )2 5 1,790) = 0.1343 (Round to four decimal places as needed.) d. Would a sample mean of 1,830 hours support the claim made by the organization? Select the correct choice below and ll in the answer box within your choice. (Round to four decimal places as needed.) \"A The probability P ()2: 1,830) = 0.3085 . This supports the claim. 3- The probability P ()2: 1 ,830) = . This contradicts the claim. e. Identify the symmetrical interval that includes 95% of the sample means if the true population mean is 1,803 hours. hours s )2 5 hours (Round to one decimal place as needed.)
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