Question: Please, I really need help on this question ASAP, I will leave you a very good review when you are done. Thank you! Question 3

 Please, I really need help on this question ASAP, I will

Please, I really need help on this question ASAP, I will leave you a very good review when you are done. Thank you!

leave you a very good review when you are done. Thank you!

Question 3 (1 point) Bohr developed his model by applying Newton's second law of motion (F = ma) to an electron. The net force is described as Coulomb's law for the interaction between an electron of charge -q that is a distance r from a proton of charge +q, that force would be F = kqq . The acceleration of the electron is in circular orbit, so the acceleration of the electron's orbit around the more massive proton is given by a = This kqq gives the equation which should look familiar. Bohr also had to look at angular momentum of the orbiting electron, which is beyond physics 30, but this is where Planck's constant comes in. Using the above classical physics and quantum ideas Bohr came up with the following equation to solve for orbital radii of the electron in a hydrogen atom. h2,2 Tn = 4x2 kmq- Determine the orbital radius, in m, of an electron in the orbital, n = (3.000x10^0) around a hydrogen atom. Note: Your answer is assumed to be reduced to the highest power possible. Your Answer: x10

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Physics Questions!