(Please if the solution can be explained)

3. This problem checks if you followed the reverse logic usage for jumping to else part. Fill in the C code for the assembly. Again use the jump-to-else-part reverse logic we used in class and also by following the practice problem 3.18 of page 213 reverse_logic: cmpq jge cmpq jle movq subq re %rsi, L3 %rdx, L4 %rdx, %rdi, %rdi %rdi %rax %rax 4: (%rdi,%rdx), Arax leaq ret 3: movq subq ret L7 %rdx, %rsi, %rax %rax 7: (Arsi,Srdx), Arax leaq ret long reverse logic(long x, long y, long z) long result; return result; 3. This problem checks if you followed the reverse logic usage for jumping to else part. Fill in the C code for the assembly. Again use the jump-to-else-part reverse logic we used in class and also by following the practice problem 3.18 of page 213 reverse_logic: cmpq jge cmpq jle movq subq re %rsi, L3 %rdx, L4 %rdx, %rdi, %rdi %rdi %rax %rax 4: (%rdi,%rdx), Arax leaq ret 3: movq subq ret L7 %rdx, %rsi, %rax %rax 7: (Arsi,Srdx), Arax leaq ret long reverse logic(long x, long y, long z) long result; return result