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1. Given that the length of the seesaw is 4 meters where force applied is on the following point . N1=2 meters , N2 =0.10 meters, N3=0.5 meters and N4=2 meters away from the pivot. Where force applied to N2= 6 N and N4= 3N. What should be the force applied to N3 and N1 in order to make the seesaw stay in static equilibrium ?(note:Summation of all torques should be O.) N2 ^N3 r1 14 N4 N1 mg1.Given that the force of static friction is 5N and the normal force is 10 N. What will be the maximum mass of the box in which it does not move in an inclined plane with 30 angle? 303. Given that the 45 Kg box attached to two string is in static equilibrium . What should tension force of each string? T1 30- 45- 45 Kg