Question: Please just say a b c or d The graph shown is f(x) = (x + 3)2. Evaluate SA ( VI + 1) dx What

Please just say a b c or d

Please just say a b c or d The graph shown is

The graph shown is f(x) = (x + 3)2. Evaluate SA ( VI + 1) dx What is the integral function g(t) that defines the area under this line between x = -3 and x = 5? O 27 8432 4 123 4 5 O 53 3 0 8 (1) = 2 /3 (1+ 3) dt 0 8 (1) = 13 ( 1+ 3)2 di O 32 3 0 8 ( 1 ) = 13 (1 + 3 ) 2 di O 28 0 8 (1) = 15 12 d1 + 9 The graph shown below is f(x) = 3x - 2. It g (x) = Sof(t) dt , what is g'(-1)? Evaluate S (2x3 + 3x2 ) dx 543240 1 23 45 0 66 30 67.5 0 5 0 3 68.5 O 1 O 70 0 - 5 The graph shown below is f (x) = 19 - X2. Evaluate 2 cos 2x dx "1 8 (x ) = [of(1) dt, what is 8' ( v5) ? O 5432 -1 12345 31 O V3 O 0 0 O 2 O V3 O 2.5 0 5 Rewrite the integral using substitution: /xV4x2 - 3 dx waves What is f(x) given the integral function f(x) = So cos(u) sin(u) dur 0 8 135 Vudu of' (x) = cosx of Vudu of' (x) = cos(x) sin(x) of'(x) = - cos(x) sin(x) 0 13 Vudu of' (x) = sin x 0 1 24 Vudu Calculus Rewrite the integral using substitution: / x2 cos(x3) dx What is f (x) given the integral function f(x) = Scos(e") dur (cosu) du of' ( x ) = x2 cos (ex? ) of (cosu) du of' (x) = 2xcos (ex?) of' (x) = -2xcos (ex?) o 125 (3cosu) du of' ( x ) = xcos (ex?) of? (3cosu) du 35 36 37

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