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Two operators handle adjustments for a group of 10 machines. Adjustment time is exponentially distributed and has a mean of 12 minutes per machine. The machines operate for an average of 68 minutes between adjustments. While running, each machine can turn out 46 pieces per hour. Find: Use Table 1. Table 2 and Table 3. a. The probability that a machine will have to wait for an adjustment. (Round your answer to 3 decimal places.) Probability b. The average number of machines waiting for adjustment. (Round your answer to 2 decimal places.) Average number of machines waiting machines c. The average number of machines being serviced (Round your answer to 2 decimal places.) Average number of machines machines d. The expected hourly output of each machine, taking adjustments into account. (Round your answer to 2 decimal places.) Expected hourly output pieces e. Machine downtime represents a cost of $62 per hour operator cost (including salary and fringe benefits) is $11 per hour. What is the optimum number of operators? 1 operator O2 operators O 3 operators A onerators