(Please provide a breakdown and describe/show step by step details on how you arrived the answers so I can learn - thanks)

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QUESTION: Shark Tank Textile manufactures textiles at plants located in Austin, TX,

Las Vegas, NV, and Los Angeles, CA. To measure employee knowledge of Six Sigma Quality, six employees were randomly selected at each plant and tested. The test scores for these employees are given in DATA (see below: 4 columns - "Observation", across the 3 plants - "Austin", "Las Vegas", "Lost Angeles"). Managers want to know if, on average, knowledge of Six Sigma is equal across the 3 plants. Test equality of mean scores at (alpha) = 0.05.

(Note: What statistical procedure is used to test equality of three population means)?)

A) The F value of 6.349 is > the F critical value of 3.682, therefore reject the equality of means. Knowledge of Six Sigma is not equal across the 3 plants.

B) The F value of 1.326 is < the F critical value of 3.682, therefore do not reject equality of means. Knowledge of Six Sigma is equal across the 3 plants.

C) The F value of 9 is > the F critical value of 3.682, therefore reject the equality of means. Knowledge of Six Sigma is not equal across the 3 plants.

D) The F value of 3.419 is < the F critical value of 3.682, therefore do not reject

equality of means. Knowledge of Six Sigma is equal across the 3 plants.

DATA:

Observation Austin Las Vegas Los Angeles

1 85 71 69

2 75 75 74

3 82 73 72

4 76 74 79

5 71 69 85

6 85 82 77