Please provide a detailed solution. I have attached the reference formulas that we are using. Thank you!

1. A kinetic energy of a 7 kg object is initially 43J. It is then subjected to a constant force so that after traveling 9.5m, its speed is doubled. Find the constant force acting on it (5 Points)The combined effect of these two variables on the acceleration of a body may be written in equation form as fsmax = /s FN (eq. 4.5) F=ma Eq. (4.1) Is = coefficient of static friction The SI unit for mass is the kilogram. Mass and weight fre= Hk FN (eq. 4.6) are related as w=mg This is known as STOKE'S LAW OF RESISTANCE FD = Bv The net force acting on an object in equilibrium is zero. my2 This is true for all objects in equilibrium. In equation form, FNsineb R FNCOSBO mg E Fnot = 0 Eq. (4.3) tanob mgsin 8 CDC Therefore, 1 = p -Po Eq. 4.4 FD = Cv2 v= designed speed mg mgcost R=radius of the curve mg - FD = 0 Representation of forces Fo=mg